Question

Five boys and three girls are seated at random in a row. The probability that no boy sits between two girls is

• A. $\frac{1}{56}$
• B. $\frac{1}{8}$
• C. $\frac{3}{28}$
• D. none of these

Answer 1

The correct option is C $\frac{3}{28}$

$n\left(s\right)=8!$
$\left(E\right)=$ The number of assingment of 5 boys and 3 girls when 3 girls are cosecutive $=6!\times 3!$
$\therefore$ Required probability $=\frac{6!\times 3!}{8!}=\frac{3}{28}$