Five capacitors are connected to each other as shown in figure. What is potential drop and charge across 4μF capacitor?
A
6 V, 24μC
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B
10 V, 30μC
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C
6 V, 40μC
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D
10 V, 40μC
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Solution
The correct option is D 10 V, 40μC The equivalent circuit is shown in the above figure. The equivalent capacitance for capacitors (6,4, 8) is C=6+4+8=18μF As all capacitors (18,C=18,18) have equal capacitance and they are in series so potential across each is V=303=10V As capacitors C contains capacitors (4,6,8) and they are in parallel so potential across each equal and it is equal to 10V. Thus charge on 4μF=4×10=40μC