Question

Five charges of each $+q$ are placed of the five corners of a regular hexagon. The resulant electric field at the centre is $E$. If the charges in the $1^{st}$ and $2^{nd}$ corner are removed, then the resultant electric field at the centre is

• A. $E$
• B. $2E$
• C. $3E$
• D. $4E$

Answer 1

The correct option is B $2E$



$E_1=E_4;E_2=E_5$ will cancel each other.

$E_3=E$

If charges at 1st and 2nd corner are removed,

$E_3=E_4=E_5=E$



The angle between $E_3$ and $E_5$ is ${120}^{\circ }$. Hence the resultant $E_{35}=E$.

The net electric filed at the centre.

$E_{net}=E+E_4=E+E=2E$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (b) is the correct answer.