Five coins were simultaneously tossed 1000 times, and at each toss the number of heads was observed. The number of tosses during which 0, 1, 1 3, 4 and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss
No. of heads per toss (x) : 0 1 2 3 4 5
No. of tosses (f) : 38 144 342 287 164 25

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Solution

Mean = $fraction numerator begin display style stack sum f subscript i x subscript i with i equals 1 below end style over denominator N end fraction$ = $fraction numerator 38 cross times 0 plus 144 cross times 1 plus 342 cross times 2 plus 287 cross times 3 plus 164 cross times 4 plus 25 cross times 5 over denominator 1000 end fraction$

Mean = = 2.47 heads per toss

Therefore mean is 2.47 heads

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No. of heads per toss (x):	0	1	2	3	4	5
No. of tosses (f):	38	144	342	287	164	25

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