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Question

Five conducting plates are placed parallel to each other Separation between them is d and area of each plate is A. Plate number 1,2 and 3 are connected with each other and at the same time through a cell of emf E. The charge on plate number 1 is
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A
Eε0A/d
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B
Eε0A/2d
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C
2Eε0A/d
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D
zero
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Solution

The correct option is A Eε0A/d
Since plates 1,2,3 are connected in parallel.
Ceq=C1+C2+C3=3ϵoAd
Toatl charges Q=CE=3ϵoAEd
so, charge through each plates=Q3=ϵoAEd

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