Five equal resistances each of resistance R are connected as shown in the figure. A battery of 4 volts is connected between A and B. The current flowing in AFCEB will be

\frac{3}{R}

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\frac{1}{R}

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\frac{1}{R}

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\frac{2}{R}

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Solution

The correct option is D $\frac{2}{R}$

Wheatstone Bridge circuit, hence resultant resistance is $R$ .
$i = \frac{4}{R}$
$i_{A F C E B} = \frac{2}{R}$

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Five equal resistances each of resistance R are connected as shown in the figure. A battery of 4 volts is connected between A and B. The current flowing in AFCEB will be

The correct option is D 2R Wheatstone Bridge circuit, hence resultant resistance is R. i=4R iAFCEB=2R

The correct option is D $\frac{2}{R}$

Wheatstone Bridge circuit, hence resultant resistance is $R$ .
$i = \frac{4}{R}$
$i_{A F C E B} = \frac{2}{R}$