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Wheatstone Bridge

Five equal re...

Question

Five equal resistances each of resistance R are connected as shown in the Figure. A battery of V volts is connected between A and B. The current flowing in AFCEB will be :

\frac{V}{R}

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\frac{V}{2 R}

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\frac{2 V}{R}

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\frac{3 V}{R}

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Solution

The correct option is A $\frac{V}{2 R}$
$R_{e q .}$ of wheatstone bridge $= R$
current in the circuit $\Rightarrow V = I R \Rightarrow I = \frac{V}{R}$
current in one branch of the wheatstone bridge= $\frac{V}{2 R}$

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