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Question

Five forces F1, F2, F3, F4 and F5 are acting on a particle of mass 2.0 kg so that it is moving with 4 m/s2 in east direction. If F1 force is removed then the acceleration becomes 7 m/s2 in north. Find the magnitude of acceleration of the block if only F1 is acting.

A
16 m/s2
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B
65 m/s2
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C
260 m/s2
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D
33 m/s2
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Solution

The correct option is B 65 m/s2
F1+F2+F3+F4+F5=2(4^i) (i)
and F2+F3+F4+F5=2(7^j) (ii)
From (i) and (ii), F1=8^i14^j
a1=F1m=4^i7^j
a1=16+49=65 m/s2

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