Five gram mol of a diatomic gas (γ=1.4) is compressed adiabatically so that its temperature rises from 127oC to 227oC. The work done will be:
A
5894.6J
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B
10392.5J
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C
9875.2J
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D
2356.4J
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Solution
The correct option is B10392.5J We know, from first law, ΔU=q+w.
For adibatic process, q=0.
Also ΔU = nCvdT and w = ΔU = nR(γ−1)(T2−T1)
= 5×R(1.4−1)(500−400)=10392.5J