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Question

Five grams of KClO3 yield 3.041 g of KCl and 1.36 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of ±0.4% error?


A

True

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B

False

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Solution

The correct option is A

True


According to gram - molecular volume law, 22.4 L of all gases and vapours at STP weigh equal to their molecular weights denoted in grams.

Weight of 1.36 L of oxygen at STP =32 × 1.3622.4=1.943 g

Weight of KCl formed = 3.041 g (given)

Total weight of product (KCl + O2)

= 3.041 + 1.943 = 4.984 g

Error = 5 - 4.984 = 0.01 6 g

% error=0.016 × 1005 =0.32

Hence, the law of conservation of mass is valid within limits of 0.4% error. Thus, the law is supported.


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