Five grams of $K C l O_{3}$ yield 3.041 g of $K C l$ and 1.36 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of $\pm 0.4 %$ error?

True

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False

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Solution

The correct option is A
True

According to gram - molecular volume law, 22.4 L of all gases and vapours at STP weigh equal to their molecular weights denoted in grams.

$∴$ Weight of 1.36 L of oxygen at STP =32 $\times$ $\frac{1.36}{22.4} = 1.943 g$

Weight of KCl formed = 3.041 g (given)

$∴$ Total weight of product (KCl + $O_{2}$ )

= 3.041 + 1.943 = 4.984 g

Error = 5 - 4.984 = 0.01 6 g

$∴ % e r r o r = 0.016$ $\times$ $\frac{100}{5}$ =0.32

Hence, the law of conservation of mass is valid within limits of $- 0.4 %$ error. Thus, the law is supported.

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Similar questions

Five grams of $K C l O_{3}$ yields 3.0 g of $K C l$ and 1.4 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of $\pm 0.4 %$ error?

Q. At STP 89.6 L of chlorine gas reacts with 560 g of

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_{3} \to

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Five grams of KClO3 yield 3.041 g of KCl and 1.36 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of ±0.4% error?

Five grams of $K C l O_{3}$ yield 3.041 g of $K C l$ and 1.36 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of $\pm 0.4 %$ error?