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Question

Five identical capacitors each of magnitude 5μF are arranged with a battery of emf 20V as shown in the figure. Initially, the switch is opened. The charge that flows from point A to point B, when the switch is closed is given as x7μC. Find x
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Solution

x7μC5+5=10μF5×55+5=2510=2.5μF
2.5+5=7.5μF7.5×107.5+10=75×1017.5=307

X=30

1227665_154944_ans_139dc84272814b28840f240103c8a200.png

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