Five identical plates are arranged such that each pair is a capacitor of capacitance 2 mF. The plates are connected to a source of emf 10 V as shown. The charge on the plate C is
A
+ 20 mC
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B
+ 40 mC
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C
+ 60 mC
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D
+ 80 mC
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Solution
The correct option is B+ 40 mC The equivalent circuit diagram,
Since C = 2mF Charge an reach capacitors is q= CV =2×10−3×10 = 20 mC Plate C participates in two capacitors. Thus, the charge an it is 40 mC