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Question

Five identical plates are arranged such that each pair is a capacitor of capacitance 2 mF.
The plates are connected to a source of emf 10 V as shown. The charge on the plate C is


A
+ 20 mC
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B
+ 40 mC
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C
+ 60 mC
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D
+ 80 mC
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Solution

The correct option is B + 40 mC
The equivalent circuit diagram,

Since C = 2mF
Charge an reach capacitors is
q= CV
=2×103×10
= 20 mC
Plate C participates in two capacitors. Thus, the charge an it is 40 mC

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