Five identical rods are joined as shown in figure- Point A and C are maintained at temperature 120- C and 20- C respectively- The temperature of junction B will beA- 50- CB- 70- CC- 0- CD- 100- C

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Conduction Law

Five identica...

Question

Five identical rods are joined as shown in figure. Point A and C are maintained at temperature $120^{\circ} C$ and $20^{\circ} C$ respectively. The temperature of junction B will be

100^{\circ} C

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50^{\circ} C

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70^{\circ} C

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0^{\circ} C

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Solution

The correct option is C $70^{\circ} C$
If thermal resistance of each rod is considered R then, the given combination can be redrawn as follows

$(H e a t c u r r e n t)_{A C} = (H e a t c u r r e n t)_{A B}$
$\frac{(120 - 20)}{2 R} = \frac{(120 - θ)}{R}$

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The correct option is C 70∘ CIf thermal resistance of each rod is considered R then, the given combination can be redrawn as follows (Heat current)AC=(Heat current)AB (120−20)2R=(120−θ)R

Five identical rods are joined as shown in figure. Point A and C are maintained at temperature $120^{\circ} C$ and $20^{\circ} C$ respectively. The temperature of junction B will be

The correct option is C $70^{\circ} C$
If thermal resistance of each rod is considered R then, the given combination can be redrawn as follows

$(H e a t c u r r e n t)_{A C} = (H e a t c u r r e n t)_{A B}$
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