Five identical rods are joined as shown in figure. Point A and C are maintained at temperature 120∘C and 20∘C respectively. The temperature of junction B will be
70∘C
If thermal resistance of each rod is considered R then, the given combination can be redrawn as follows
(Heat current)AC=(Heat current)AB
(120−20)2R=120−θR⇒θ=70∘C