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Question

Five identical rods are joined as shown in figure. Points A and C are maintained at temperature 120C and 20C respectively. The temperature of junction B will be

A
100 C
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B
80 C
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C
70 C
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D
0 C
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Solution

The correct option is C 70 C
If thermal resistance of each rod is considered R then, the given combination can be redrawn as follows,

From above figure, there are two paths for flow of heat from B to C each having resistance 2R and connected in parallel.
Hence, we can deduce that effective resistance between B and C is R

As AB and BC are connected in series

(Thermal current)AB=(Thermal current)BC
(120θ)R=(θ20)Rθ=70 C.

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