The correct option is C 20
Let the numbers in continued proportion be a, ak, ak2, ak3, ak4.
Given first term is 5 so, a=5 and last term is 80 so, ak4=80.
⇒ak4=80
⇒5k4=80
⇒k4=16
⇒k=2
Hence the five numbers are 5, 10, 20, 40, 80. The third number will be 20.