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Byju's Answer
Standard IX
Mathematics
Direct Proportionality
Five numbers ...
Question
Five numbers are in continued proportion where the first term is 1 and the last term is 256. Find the numbers.
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Solution
Let
t
h
e
five
numbers
in
continued
proportion
b
e
a
,
a
k
,
a
k
2
,
a
k
3
a
n
d
a
k
4
.
G
i
v
e
n
:
a
=
1
and
a
k
4
=
256
T
h
u
s
,
w
e
h
a
v
e
:
a
k
4
a
=
256
1
⇒
k
4
=
256
⇒
k
=
4
A
n
d
,
a
k
=
4
∴
a
k
2
=
1
×
16
=
16
⇒
a
k
3
=
1
×
64
=
64
Thus
,
the
numbers
are
1
,
4
,
16
,
64
and
256
.
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