Five numbers are in HP. The middle term is 1 and the ratio of the second and the fourth terms is 2:1. Then, the sum of the first three terms is
A
112
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B
5
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C
2
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D
143
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Solution
The correct option is A112 Let a−2d,a−d,a+d,a+2d are in AP then 1a−2d,1a−d,1a+d,1a+2d are in HP Given, middle term =1 ⇒1a=1 and Second termFirst term=21 ⇒1a−d×(a+d)=21 ⇒a=3d⇒d=13 (∵a=1) ∴ Sum of first three terms =11−23+11−13+1=3+32+1=112