Question

Five particles of masses $2$ kg each are attached to the circumference of circular disc of a radius $0.1$m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is?

• A. $1$ kg $m^2$
• B. $0.1$kg $m^2$
• C. $2$ kg $m^2$
• D. $0.2$ kg $m^2$

Answer 1

The correct option is B $0.1$kg $m^2$

The moment of inertia of the given system that contains 5 particles each of mass = 2 kg on the rim of circular disc of radius 0.1 m and of negligible mass is given by .=momentofinertiaofdisc$+$momentofinertiaofparticle Since, the mass of the disc is negligible therefore, MI of the system = MI of particle $=5\times 2\times {\left(0.1\right)}^2=0.1kg-m^2$