Question

Five persons A, B, C, D and E occupy seats in a row such that A and B sit next to each other. In how many possible ways can these five people sit?

• A. 24
• B. 48
• C. 72
• D. 56

Answer 1

The correct option is B 48

(B) $4!\times 2$ ways. i.e, $24\times 2=48$ ways