Question

Five point charges, each of charge $+q$ are placed on five vertices of a regular hexagon of side $h$ as shown in the figure. Then

• A. the forces on $(-q)$ at $O$ due to charges $+q$ at $A$ and $D$ are balanced.
• B. the forces on $(-q)$ due to charges at $$D$and$E$ are balanced.
• C. the resultant forces $-q$ at $O$ is $\frac{1}{4\pi {\epsilon }_0}\frac{q^2}{h^2}$ along $OE$.
• D. The resultant force on $-q$ at $O$ $\frac{1}{4\pi {\epsilon }_0}\frac{q^2}{h^2}$ along $OC$.

Answer 1

Answer: (A), (D)

The correct options are
A the forces on $(-q)$ at $O$ due to charges $+q$ at $A$ and $D$ are balanced.
D The resultant force on $-q$ at $O$ $\frac{1}{4\pi {\epsilon }_0}\frac{q^2}{h^2}$ along $OC$.

As -q is negatively charged and forces due to charge at E and D cancels the effect due to B and A respectively. So net force will be n the direction of O to C which satisfy attracting nature.

$F_{\left(OC\right)}=\frac{Kq\left(q^{\prime }\right)}{h^2}$

$F=\frac{q^2}{4\pi {\epsilon }_o{h}^2}$