The correct option is A 1 A
Given,
Resistance values,
R1=R2=R3=3 Ω
R4=R5=0.5 Ω
Here the resistances R1 and R2 are in series. Let the equivalent resistance of this combination be R12.
R12=R1+R2
R12=3+3=6 Ω
Now R12 and R3 are in parallel.
Let the equivalent resistance of this combination be R123.
⟹1R123=1R12+1R3
1R123=16+13
R123=2 Ω
Now, R4, R123 and R5 are in series.
Let the equivalent resistance of this combination be R.
⟹R=R4+R123+R5
R=0.5+2+0.5 Ω
R=3 Ω
Using Ohms law,
I=VR
I=3 V3 Ω=1 A