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Question

Five resistors are connected in circuit as shown with a 3 V battery. Find the ammeter reading.


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Solution

Given,
Resistance values,
R1=R2=R3=3 Ω
R4=R5=0.5 Ω

Here the resistances R1 and R2 are in series. Let the equivalent resistance of this combination be R12.
R12=R1+R2
R12=3+3=6 Ω

Now R12 and R3 are in parallel.
Let the equivalent resistance of this combination be R123.

1R123=1R12+1R3
1R123=16+13
R123=2 Ω

Now, R4, R123 and R5 are in series.
Let the equivalent resistance of this combination be R.

R=R4+R123+R5
R=0.5+2+0.5 Ω
R=3 Ω

Using Ohms law,
I=VR
I=3 V3 Ω=1 A

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