Five sticks of length $1, 3, 5, 7$ and $9$ feet are given. Three of these sticks are selected at random. What is the probability that the selected sticks can form a triangle?

0.5

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0.4

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0.3

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0.2

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Solution

The correct option is D $0.2$
Total number of cases = $C (5, 3) = 10$

Probable cases $= (3, 5, 7)$ and $(5, 7, 9) = 2$
(sum of the two smallest sides must be greater than the third one)

$∴$ probability = $\frac{2}{10} = 0.2$

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Five sticks of length 1,3,5,7 and 9 feet are given. Three of these sticks are selected at random. What is the probability that the selected sticks can form a triangle?

The correct option is D 0.2Total number of cases = C(5,3)=10Probable cases =(3,5,7) and (5,7,9)=2(sum of the two smallest sides must be greater than the third one)∴ probability = 210=0.2

Five sticks of length $1, 3, 5, 7$ and $9$ feet are given. Three of these sticks are selected at random. What is the probability that the selected sticks can form a triangle?

The correct option is D $0.2$
Total number of cases = $C (5, 3) = 10$

Probable cases $= (3, 5, 7)$ and $(5, 7, 9) = 2$
(sum of the two smallest sides must be greater than the third one)

$∴$ probability = $\frac{2}{10} = 0.2$