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Question

Five years ago a man was seven times as old as his son. Five years hence, The father will be three times as old as his son. Find their present ages.

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Solution

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

7x+10=3(x+10)

7x3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years
and the present age of father=7x+5=35+5=40years

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