Five years ago Jayden was six times older than his son. After five years, Jayden will be 10 years more than two times the age of his son. Find the present age of Jayden and his son by elimination method

Open in App

Solution

Dear Student.

$L e t t h e c u r r e n t a g e o f J a y d e n a n d h i s s o n b e x a n d y y e a r s r e s p e c t i v e l y . 5 y e a r s a g o, J a y d e n' s a g e = x - 5 y e a r s S o n' s a g e = y - 5 y e a r s A c c o r d i n g t o q u e s t i o n : (x - 5) = 6 (y - 5) x - 5 = 6 y - 30 x - 6 y = - 25 . . . (i) A l s o, 5 y e a r s l a t e r : x + 5 = 2 (y + 5) + 10 x + 5 = 2 y + 10 + 10 = > x - 2 y = 15 . . . (i i) S u b t r a c t i n g e q (i) f r o m (i i) 2 y + 6 y = 15 + 25 4 y = 40 y = 10 P u t t i n g y i n (i i) x - 2 \times 10 = 15 x = 35 S o, a g e o f J a y d e n i s 5 y e a r s a n d a g e o f s o n i s 10 y e a r s .$

We hope that this answer solves your query.
Regards.

Suggest Corrections

Similar questions

Q. Two years ago, a man was five times as old as his son. Two years later, his age will be 8 more than three times the ago of the son. Find the present ages of the man and his son.

Q. A man is 24 years older than his son. 12 years ago, he was five times as old as his son. Find the present ages of both.

Q. Five years hence, father's age will be three times the age of his son. Five years ago, father was seven times as old as his son. Find their present ages

Q. The sum of the present ages of a father and his son is 60 years. Six years ago father's age was five times the age of the son After six years son's age will be-

The sum of the present ages of a father and his son is 60 years. Six years ago, the father's age was five times the age of his son. After 6 years, the son's age will be:

Join BYJU'S Learning Program