Fixed mass of a gas is subjected to the changes as shown is diagram, calculate $T_{3}, T_{4}, P_{1}, P_{2}$ and $V_{1}$ as shown is diagram. Considering gas obeys $P V = n R T$ equation.

Open in App

Solution

$10 (4) = 8 (P_{1}) [Boyle's Law \to constant temperature] P_{1} = 5 a t m for constant volume P \propto T \Rightarrow \frac{P_{1}}{3} = \frac{T_{2}}{T_{3}} \Rightarrow \frac{5}{3} = \frac{600}{T_{3}} \Rightarrow T_{3} = 360 K At constant pressure, V \propto T \Rightarrow \frac{8}{V_{1}} = \frac{300}{600} \Rightarrow V_{1} = 16 l i t r e s \frac{(3) (V_{1})}{T_{3}} = \frac{P_{2} (8)}{T_{4}} \Rightarrow \frac{P_{2}}{T_{4}} = \frac{6}{360} 60 P_{2} = T_{4}$

Suggest Corrections

Similar questions

(p_{1}, v_{1})

(p_{2}, v_{2})

p V = n R T

P (V - b) = n R T

S T P

L

P V = n R T

Join BYJU'S Learning Program