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Standard XII

Chemistry

Collision Theory

Flask A of vo...

Question

Flask A of volume 10 litre containing 20 g of $H_{2}$ and flask B of volume 10 litre containing 88 g $C O_{2}$ are connected by a connector having negligible volume. When valve of the connector is opened, what is that composition of $H_{2}$ gas in flask B after opening the valve?

10%

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83.33%

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15%

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20%

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Solution

The correct option is A 83.33%
The number of moles of hydrogen in flask A $= \frac{20}{2} = 10$ .
The number of moles of carbon dioxide in flask B $= \frac{88}{44} = 2$ .
Total number of moles $= 10 + 2 = 12$ .
When the valve is opened, the mixture will be uniform in two flasks.
Hence, the composition of hydrogen in flask B will be $\frac{10}{12} \times 100 = 83.33$ %.

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Flask A of volume 10 litre containing 20 g of H2 and flask B of volume 10 litre containing 88 g CO2 are connected by a connector having negligible volume. When valve of the connector is opened, what is that composition of H2 gas in flask B after opening the valve?

Flask A of volume 10 litre containing 20 g of $H_{2}$ and flask B of volume 10 litre containing 88 g $C O_{2}$ are connected by a connector having negligible volume. When valve of the connector is opened, what is that composition of $H_{2}$ gas in flask B after opening the valve?