Flow of electrons in ETS is

F e + + \to {C u}^{+} > F e + +

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F e + + \to F e + +

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{F e}^{+ 3} \to {F e}^{+ 2} \to {F e}^{+ 3}

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{F e}^{+ 2} \to {F e}^{+ 3} \to {F e}^{+ 2}

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Solution

The correct option is A $F e + + \to {C u}^{+} > F e + +$

NADH dehydrogenase has two prosthetic groups - flavin mononuclear ( FMN ) and iron-sulfur ( Fe-S ) complexes. Electrons and protons pass from NADH to FMN. Electrons now move to Fe-S complex and from there to quinone, also called as ubiquinone. This charged ubiquinone picks up a proton and with the help of cyt b passes it to the outer chamber.
2e $^{-}$ + 2Fe $^{3}$ $^{+}$ + S $\to$ 2Fe $^{2}$ $^{+}$ S
2Fe $^{2}$ $^{+}$ S + Q $\to$ 2Fe $^{3}$ $^{+}$ S + Q $^{2}$ $^{-}$
This occurs in complex 1 of electron transport system.

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Similar questions

F e | F e^{2 +} | | F e^{3 +} | F e

F e | F e^{2 +} | | F e^{3 +}, F e^{2 +} | P t

F e | F e^{3 +} | | F e^{3 +}, F e^{2 +} | P t

(E^{o})

F e^{3 +} \to F e

F e^{2 +} + 2 e 6 - \to F e; E_{F}^{o} e_{F e^{2 +} / F e} = - 0.47 V

F e^{3 +} + e^{-} \to F e^{2 +}; E_{F e^{3 +} / F e^{2 +}}^{o} = + 0.77 V

E_{{F e}^{2 +} / F e}^{o} = - 0.44 V E_{{F e}^{3 +} / {F e}^{2 +}}^{o} = 0.77 V

F e + 2 {F e}^{3 +} \to 3 {F e}^{2 +}

E^{o} :

(E^{o})

F e^{3 +} \to F e

F e^{2 +} + 2 e^{-} \to F e; E_{F e^{2 +} / F e}^{o} = - 0.47 V

F e^{3 +} + e^{-} \to F e^{2 +}; E_{F e^{3} / F e^{2 +}}^{o} = + 0.77 V

E_{{F e}^{2 +} | F e}^{o} = - 0.44 V

E_{{F e}^{3 +} | {F e}^{2 +}}^{o} = - 0.77 V

E_{{{F e}^{3 +} | F e}^{o}}^{o}

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