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Question

Fluorine reacts with ice and results in the change:
H2O(s)+F2(g)HF(g)+HOF(g)
i) Justify that this reaction is a redox reaction.
ii) Write the substances oxidized and reduced.
iii) Write the name of the substances which acts as reducing agent and oxidizing agent.

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Solution

H2O+F2HF+HOF

oxidation number of F in F2=0

oxidation number of F in HF=1

oxidation number of F in HOF=+1

Here,we see oxidation number ofFedecreases from zero to1(HF) and increase from +1(HOF). This shows thatF2is both reduced as well as oxidised. hence, it is a redox reaction and more specifically , it is a disproportionation redox reaction.


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