Fluorine reacts with ice and results in the change-H 2 O s - F 2 g - HF g - HOF g Justify that this reaction is a redox reaction-

Let us write the oxidation number of each atom involved in the given reaction above its symbol as: +1H_2 2O+0F_2⟶+1H 1F++1H 2O+1F Here, we have observed that th ...

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Standard XII

Chemistry

Redox Reactions

Fluorine reac...

Question

Fluorine reacts with ice and results in the change:
$H_{2} O (s) + F_{2} (g) \to H F (g) + H O F (g)$
Justify that this reaction is a redox reaction.

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Solution

Let us write the oxidation number of each atom involved in the given reaction above its symbol as:
$_{2} - 2 O +_{2} ⟶ + 1 H - 1 F + + 1 H - 2 O + 1 F$
Here, we have observed that the oxidation number of F increases from 0 in $F_{2}$ to +1 in HOF. Also, the oxidation number decreases from 0 in $F_{2}$ to -1. Thus, in the above reaction, F is both oxidized and reduced. Hence, the given reaction is a redox reaction.

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Redox Reactions

Standard XII Chemistry

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Fluorine reacts with ice and results in the change: H2O(s)+F2(g)→HF(g)+HOF(g) Justify that this reaction is a redox reaction.

Fluorine reacts with ice and results in the change:
$H_{2} O (s) + F_{2} (g) \to H F (g) + H O F (g)$
Justify that this reaction is a redox reaction.