Flux - in weber in a closed circuit of resistance 10 ohm varies with time t in sec according to the equation - -6 t 2 -5t-1 - What is the magnitude of the induced current at t - 1 sec-

The correct option is D 0.7A Given, flux ϕ=6t^2 5t+1 The magnitude of induced emf , |ε|=| dϕdt|=12t 5 Induced current , I=|ε|R=12t 510 at ...

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Standard XII

Physics

Inductors in Circuits

Flux Φ in w...

Question

Flux $Φ$ (in weber) in a closed circuit of resistance 10 ohm varies with time t (in sec) according to the equation $Φ = 6 t^{2} - 5 t + 1$ . What is the magnitude of the induced current at t = 1 sec?

0.5 A

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0.6 A

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0.7 A

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0.8 A

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Solution

The correct option is D $0.7 A$
Given, flux $ϕ = 6 t^{2} - 5 t + 1$

The magnitude of induced emf , $| ε | = | - \frac{d ϕ}{d t} | = 12 t - 5$

Induced current , $I = \frac{| ε |}{R} = \frac{12 t - 5}{10}$

at $t = 1,$ $I = (12 - 5) / 10 = 0.7 A$

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Flux Φ (in weber) in a closed circuit of resistance 10 ohm varies with time t (in sec) according to the equation Φ=6t2−5t+1 . What is the magnitude of the induced current at t = 1 sec?

The correct option is D 0.7AGiven, flux ϕ=6t2−5t+1The magnitude of induced emf , |ε|=|−dϕdt|=12t−5Induced current , I=|ε|R=12t−510at t=1, I=(12−5)/10=0.7A

Flux $Φ$ (in weber) in a closed circuit of resistance 10 ohm varies with time t (in sec) according to the equation $Φ = 6 t^{2} - 5 t + 1$ . What is the magnitude of the induced current at t = 1 sec?

The correct option is D $0.7 A$
Given, flux $ϕ = 6 t^{2} - 5 t + 1$

The magnitude of induced emf , $| ε | = | - \frac{d ϕ}{d t} | = 12 t - 5$

Induced current , $I = \frac{| ε |}{R} = \frac{12 t - 5}{10}$

at $t = 1,$ $I = (12 - 5) / 10 = 0.7 A$