CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Focal length of a thin convex lens is 30 cm. At a distance of 10 cm from the lens, there is a plane refracting surface of refractive index 3/2. Where will the parallel rays incident on the lens converge?
1397948_9c350d67b378457bac06e532e7e20223.jpg

A
At a distance of 27.5cm from the lens
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
At a distance of 25cm from the lens
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
At a distance of 45cm from the lens
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
At a distance of 40cm from the lens
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is A At a distance of 40cm from the lens
The lens will converge the rays at its focus, i.e., 30 cm from the lens or 20 cm from the refracting surface.
PI1=20 cm
PI2=μ(PI1)=32×20=30 cm
So, the rays will converge at a distance of 40 cm from the lens.
1588451_1397948_ans_d9b298c9a00846c88b2435460374d2ae.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thin Lenses: Point Objects
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon