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Combinations of Lenses & Mirrors

Focal length ...

Question

Focal length of the objective and eyelenses of a telescope are 200 cm and 5 cm. The maximum magnifying power of the telescope is

A

40

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B

48

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C

60

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D

100

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Solution

The correct option is B 48
$m = \frac{f_{0}}{f_{e}} [1 + \frac{f_{e}}{D}] m = \frac{200}{5} [1 + \frac{5}{25}] = 40 [1 + \frac{1}{5}] = 40 \times \frac{6}{5} = 8 \times 6 m = 48$

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