Foci of the Ellipse $25 x^{2} + 9 y^{2} - 150 x - 90 y + 225$ = 0 are

(3,9) (3,1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(4,9) (4,1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(5,7) (4,7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(6,9) (5,1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
(3,9) (3,1)

$25 x^{2} + 9 y^{2} - 150 x - 90 y + 225$ = 0

$25 (x^{2} - 6 x) + 9 (y^{2} - 10 y)$ = -225

$25 (x - 3)^{2} + 9 (y - 5)^{2}$ =225 $\Rightarrow$ $\frac{(x - 3)^{2}}{9} + \frac{(y - 5)^{2}}{25}$ = 1

e = $\frac{4}{5}$ , S = (h, k $\pm$ be) = (3,5 $\pm$ 4) = (3,9) and (3,1)

Suggest Corrections

Similar questions

25 x^{2} + 9 y^{2} - 150 x - 90 y + 225 = 0

Foci of the Ellipse $25 x^{2} + 9 y^{2} - 150 x - 90 y + 225$ = 0 are

25 x^{2} + 9 y^{2} - 150 x - 90 y + 225 = 0,

e

25 x^{2} + 9 y^{2} + 50 x + 36 y - 164 = 0

25 x^{2} + 36 y^{2} = 225

Join BYJU'S Learning Program