Question

Following are the ionisation potential values of :

$\left(I_1\right)899kJmo{l}^{-1},\left(I_2\right)1757kJmo{l}^{-1},\left(I_3\right)15000kJmo{l}^{-1}$

• A. Na
• B. K
• C. Be
• D. Ne

Answer 1

The correct option is C Be

The above values of ionization enthalpies represent the $IP$ values of $Be$ as the charge increases the IP values increases and the $I{P}_3$ value is suddenly increased a lot due to attainment of duplet configuration of $Be$.

So, it requires more energy to remove the electron from an element of duplet configuration.

Hence option C is correct.