Question

Following are the marks obtained by 9 students in Mathematics test: $50,69,20,33,53,39,40,65,59$ The mean deviation from the median is

• A. $9$
• B. $10.5$
• C. $12.67$
• D. $14.76$

Answer 1

The correct option is C $12.67$

Arranging the given data in ascending order
$20,33,39,40,50,53,59,65,69$
Here, $n=9\left(odd\right)$
Median $M=\text{Value of}{5}^{th}\text{observation}$
So, Median is 50.
Now, mean deviation above median$=\frac{1}{n}\sum |x_i-M|$
$=\frac{114}{9}=12.67$