Following are the thermochemical reactions: C (graphite) +12O2→CO;ΔH=−110.5 kJ/mol CO+12O2→CO2;ΔH=−283.2 kJ/mol
The heat of reaction (in kJ/mol) for the following reaction is:
C(graphite)+O2→CO2
A
+393.7
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B
−393.7
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C
−172.7
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D
+172.7
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Solution
The correct option is B−393.7 The thermochemical reactions are as given below: C (graphite) +12O2→CO;ΔH=−110.5 kJ/mol ...(1) CO+12O2→CO2;ΔH=−283.2 kJ/mol ......(2) The above two reactions are added to obtain the following reaction:
C (graphite) +O2→CO2 By applying Hess's law, the enthalpy change will be −110.5+(−283.2)=−393.7 kJ/mol
Hence, the heat of the given reaction is −393.7 kJ/mol.