Following are the values of a function yx- y-1 - 5- y1 - 8- dy-dx at x - 0 as per Newton-s central difference scheme is

Given: nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; y( 1) = 5 nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; ...

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Standard XII

Mathematics

Derivative Operator dy/dx

Following are...

Question

Following are the values of a function y(x): y(-1) = 5, y(1) = 8, $\frac{d y}{d x}$ at x = 0 as per Newton's central difference scheme is

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1.5

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2.0

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3.0

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Solution

The correct option is B 1.5
Given:
y(-1) = 5
y(1) = 8

$(\frac{d y}{d x})_{x = 0} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{y (1) - y (- 1)}{1 - (- 1)}$
$(\frac{d y}{d x})_{x = 0} = \frac{8 - 5}{2} = 1.5$

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Following are the values of a function y(x): y(-1) = 5, y(1) = 8, dydx at x = 0 as per Newton's central difference scheme is

The correct option is B 1.5Given: y(-1) = 5 y(1) = 8 (dydx)x=0=y2−y1x2−x1=y(1)−y(−1)1−(−1) (dydx)x=0=8−52=1.5

Following are the values of a function y(x): y(-1) = 5, y(1) = 8, $\frac{d y}{d x}$ at x = 0 as per Newton's central difference scheme is

The correct option is B 1.5
Given:
y(-1) = 5
y(1) = 8

$(\frac{d y}{d x})_{x = 0} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{y (1) - y (- 1)}{1 - (- 1)}$
$(\frac{d y}{d x})_{x = 0} = \frac{8 - 5}{2} = 1.5$