wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Following data has been given for CO2 for the concentration in H2O.
TemperatureHenry's constantPressure273 K728 atm0.10 atm333 K3410 atmp2
If solution of CO2 in H2O is heated from 273 K to 333K, pressure (p2) needed to keep CO2 in the solution is :

A
0.108 atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.805 atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.212 atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.468 atm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.468 atm
Henry Law : The solubility of a gas in a liquid at a given temperature is directly proportional to its partial pressure of the gas present above the solution.

Given,
At 273K,
KH=728 atm
Partial pressure of gas, p1=0.10 atm
By Henry's law,
p=KH×χ
Thus, ​
χCO2(mole fraction of CO2)=pKH=0.10728
At 333K
By Henry's law:

χCO2=pKH=p23410

p23410=0.10728

p2=0.10×3410728=0.468 atm
Thus, the partial pressure required to keep CO2 in the solution at 333 K is 0.468 atm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Gases in Liquids and Henry's Law
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon