Following data is available about 3 nuclei P, Q and R. Arrange them in decreasing order of stability.
PQRNo.of protons523No. of neutrons533Binding energy(MeV)1006066
P>R>Q
Q>R>P
Q=R>P
R>P>Q
(BEA)P=10010=10(BEA)Q=605=12(BEA)R=666=11∴Q>R>P
If 2p.3q.5r=60, which of the following is true? Given; p, q, r are natural numbers.
p3+ q3 + r3 – 3pqr = ?