Following enthalpy changes are given: α−Dglucose(s)→α−Dglucose(aq);ΔH=10.72kJ β−Dglucose(s)→β−Dglucose(aq);ΔH=4.68kJ α−Dglucose(s)→β−Dglucose(aq);ΔH=1.16kJ Calculate enthalpy change in α−Dglucose(s)→β−Dglucose(s) (n kJ)
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Solution
α−Dglucose(s)→α−Dglucose(aq);ΔH=10.72kJ β−Dglucose(s)→β−Dglucose(aq);ΔH=4.68kJ α−Dglucose(s)→β−Dglucose(aq);ΔH=1.16kJ It can be seen that, (i) - (ii) - (iii) = α−Dglucose(s)→β−Dglucose(s)ΔH=10.72kJ−4.68−1.16=4.88kJ