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Question

Following enthalpy changes are given:
αDglucose(s)αDglucose(aq);ΔH=10.72kJ
βDglucose(s)βDglucose(aq);ΔH=4.68kJ
αDglucose(s)βDglucose(aq);ΔH=1.16kJ
Calculate enthalpy change in
αDglucose(s)βDglucose(s) (n kJ)

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Solution

αDglucose(s)αDglucose(aq);ΔH=10.72kJ
βDglucose(s)βDglucose(aq);ΔH=4.68kJ
αDglucose(s)βDglucose(aq);ΔH=1.16kJ
It can be seen that,
(i) - (ii) - (iii) =
αDglucose(s)βDglucose(s) ΔH=10.72kJ4.681.16=4.88kJ

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