Following enthalpy changes are given- -D glucoses-D glucoseaq- - H - 10-72 kJ -D glucoses-D glucoseaq- - H - 4-68 kJ -D glucoses-D glucoseaq- - H - 1-16 kJCalculate enthalpy change in -D glucoses-D glucoses

The correct option is D 4.88 kJ α D #160;glucose(s)→α D #160;glucose(aq); Δ H = 10.72 #160;kJ β D #160;glucose(s)→β D #160;gluco ...

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Enthalpy

Following ent...

Question

Following enthalpy changes are given:
$α - D g l u c o s e (s) \to α - D g l u c o s e (a q); Δ H = 10.72 k J$
$β - D g l u c o s e (s) \to β - D g l u c o s e (a q); Δ H = 4.68 k J$
$α - D g l u c o s e (s) \to β - D g l u c o s e (a q); Δ H = 1.16 k J$
Calculate enthalpy change in
$α - D g l u c o s e (s) \to β - D g l u c o s e (s)$

14.24 k J

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16.56 k J

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- 7.2 k J

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4.88 k J

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α - D g l u c o s e (s) ⟶ α - D g l u c o s e (a q .); Δ H = 10.72 k J

β - D g l u c o s e (s) ⟶ β - D g l u c o s e (a q .); Δ H = 4.68 k J

α - D g l u c o s e (a q .) ⟶ β - D g l u c o s e (a q .); Δ H = 1.16 k J

α - D g l u c o s e (s) ⟶ β - D g l u c o s e (s)

α - D - g l u c o s e_{(s)} + H_{2} O ⟶ α - D - g l u c o s e_{(a q)}; Δ H_{d i s s o l u t i o n} = 10.84 k J

β - D - g l u c o s e_{(s)} + H_{2} O ⟶ β - D - g l u c o s e_{(a q)}; Δ H_{d i s s o l u t i o n} = 4.68 k J

α - D - g l u c o s e_{(a q)} ⟶ β - D - g l u c o s e_{(a q)}; Δ H_{m u t a r o t a t i o n} = - 1.16 k J

Δ H^{\circ}

α - D - g l u c o s e ⟶ β - D - g l u c o s e

Z = 92

α, α, β^{-}, β^{-}, α, α, α, α, β^{-}, β^{-}, α, β^{+}, β^{+}, α

Z

Z = 92

α, α, β^{-}, β^{-}, α, α, α, α; β^{-}, β^{-}, α, β^{+}, β^{+}, α

Z

Z = 92

α, β^{-}, β^{-}, α, α, α, α, α, β^{-},

β^{-}, α, β^{+}, β^{+}, α

Z

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