Following forces start acting on a particle at rest at the origin of the co-ordinate system simulaneously F 1-4 -5 -5 k- F 2-5 -8 -6 k- F 3-3 -4 -7 k- and F 4-2 -3 -2 k- then the particle will moveA- in x - y planeB- in y - Z planeC- in x-z planeD- along x - axis

The correct option is B in y z nbsp; plane⇒F⃗_⃗1⃗+F⃗_⃗2⃗+F⃗_⃗3⃗+F⃗_⃗4⃗ ⇒( 4î 5ĵ+5k̂)+(5î+8ĵ+6k̂) +( 3î+4ĵ 7k̂)+(2î 3ĵ 2k̂) ⇒ (0î 4ĵ 2k̂) So, the particle wil ...

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Byju's Answer

Standard XII

Physics

Vector Addition

Following for...

Question

Following forces start acting on a particle at rest at the origin of the co-ordinate system simulaneously $_{1} = - 4^i - 5^j + 5^k$ , $_{2} = 5^i + 8^j + 6^k$ , $_{3} = - 3^i + 4^j - 7^k$ and $_{4} = 2^i - 3^j - 2^k$ then the particle will move

x - y

plane

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y - z

plane

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x - z

plane

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along

x -

axis

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Solution

The correct option is B in $y - z$ plane
$\Rightarrow_{1} +_{2} +_{3} +_{4}$
$\Rightarrow (- 4^i - 5^j + 5^k) + (5^i + 8^j + 6^k) + (- 3^i + 4^j - 7^k) + (2^i - 3^j - 2^k)$
$\Rightarrow (0^i - 4^j - 2^k)$
So, the particle will move in $y - z$ plane

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Similar questions

Q. Following forces start acting on a particle at rest at the origin of the co-ordinate system simultaneously

_{1} = - 4^i - 5^j + 5^k,_{2} = - 5^i + 8^j + 6^k,_{3} = - 3^i + 4^j - 7^k

and

_{4} = 12^i - 3^j - 2^k

then the particle will move

Q. Show that the four points vectors

4^i + 8^j + 12^k, 2^i + 4^j + 6^k, 3^i + 5^j + 4^k

and

5^i + 8^j + 5^k

are co-planar.

Q. Show that the four points with position vectors

4^i + 8^j + 12^k, 2^i + 4^j + 6^k, 3^i + 5^j + 4^k

and

5^i + 8^j + 5^k

are coplanar.

Q. Three forces

_{1} = 2^i - 4^j + 5^k

_{2} =^i + 3^j - 8^k

and

_{3} = - 6^i - 10^j + 7^k

are acting on a particle present on the positive

x

axis,

5 units

away from the origin. The three forces combined displace the body to a point

6 ˆ i - 3 ˆ j + 10 ˆ k

. What is the net work done by the three forces ?

A body, initially at rest, is acted upon by four forces $_{1} =^i +^k,_{2} = 2^j + 3^k,_{3} = 3^i$ and $_{4} = 3^j - 4^i$ . In which plane will the body move?

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Following forces start acting on a particle at rest at the origin of the co-ordinate system simulaneously →F1=−4^i−5^j+5^k, →F2=5^i+8^j+6^k, →F3=−3^i+4^j−7^k and →F4=2^i−3^j−2^k then the particle will move

The correct option is B in y−z plane⇒→F1+→F2+→F3+→F4 ⇒(−4^i−5^j+5^k)+(5^i+8^j+6^k)+(−3^i+4^j−7^k)+(2^i−3^j−2^k) ⇒(0^i−4^j−2^k) So, the particle will move in y−z plane

Following forces start acting on a particle at rest at the origin of the co-ordinate system simulaneously $_{1} = - 4^i - 5^j + 5^k$ , $_{2} = 5^i + 8^j + 6^k$ , $_{3} = - 3^i + 4^j - 7^k$ and $_{4} = 2^i - 3^j - 2^k$ then the particle will move

The correct option is B in $y - z$ plane
$\Rightarrow_{1} +_{2} +_{3} +_{4}$
$\Rightarrow (- 4^i - 5^j + 5^k) + (5^i + 8^j + 6^k) + (- 3^i + 4^j - 7^k) + (2^i - 3^j - 2^k)$
$\Rightarrow (0^i - 4^j - 2^k)$
So, the particle will move in $y - z$ plane