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Byju's Answer
Standard XII
Mathematics
Differentiabilty
Following fun...
Question
Following function is continous at
x
=
0
f
(
x
)
=
⎧
⎪
⎨
⎪
⎩
x
,
x
>
0
1
,
x
=
0
−
x
,
x
<
0
A
True
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B
False
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Solution
The correct option is
B
False
Given function is
f
(
x
)
=
⎧
⎪
⎨
⎪
⎩
x
x
>
0
1
x
=
0
−
x
x
<
0
lim
x
→
0
+
f
(
x
)
=
0
lim
x
→
0
−
f
(
x
)
=
0
f
(
0
)
=
1
⟹
lim
x
→
0
+
f
(
x
)
=
lim
x
→
0
−
f
(
x
)
≠
f
(
0
)
So the Function is not continous at
x
=
0
Suggest Corrections
0
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