Question

Following graph shows a variation of ionization potential with atomic number in the second period ($Li-Ne$). Value of ionization potential of $Na\left(11\right)$ will be:

• A. above $Ne$
• B. below $Ne$ but above $O$
• C. below $Li$
• D. between $N$ and $O$

Answer 1

The correct option is C below $Li$

The value of the ionization potential of $Na\left(11\right)$ will be below $Li$.
In a group, I.P. decreases from top to bottom, atomic size increases and the nuclear attraction for valence electrons decreases.