Following is square shape loop, whose one arm $B C$ produces magnetic field $B$ at the center of coil. The resultant magnetic field due to all the arms will be:-

4 B

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B / 2

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B

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2 B

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Solution

The correct option is A $4 B$
Due to $B C$ at $0 = B ˆ k$
Due to $C D$ at $0 = B ˆ k$
Due to $D A$ at $0 = B ˆ k$
Due to $A B$ at $0 = B ˆ k$
Net magnetic field= $4 B ˆ k$

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Following is square shape loop, whose one arm BC produces magnetic field B at the center of coil. The resultant magnetic field due to all the arms will be:-

The correct option is A 4BDue to BC at 0=BˆkDue to CD at 0=BˆkDue to DA at 0=BˆkDue to AB at 0=BˆkNet magnetic field=4Bˆk

Following is square shape loop, whose one arm $B C$ produces magnetic field $B$ at the center of coil. The resultant magnetic field due to all the arms will be:-

The correct option is A $4 B$
Due to $B C$ at $0 = B ˆ k$
Due to $C D$ at $0 = B ˆ k$
Due to $D A$ at $0 = B ˆ k$
Due to $A B$ at $0 = B ˆ k$
Net magnetic field= $4 B ˆ k$