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Question

Following is the frequency distribution of the total marks obtained by the students of all sections of a class in an examination. ​
Draw a histogram to represent the provided data.​

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Solution

Class width = Upper limit – Lower limit
For 100150
Class width =150100=50
Similarly,

Class width of 150200=50
Class width of 200300=100
Class width of 300600=300
Class width of 600800=200
Now,
Adjusted frequency = minimum class sizeclass size of this class×frequency

Here, the minimum class size =50.
Now,
Adjusted frequency of class interval 300600 is.

Adjusted frequency = 50300×60 =10.
Similarly,

Adjusted frequency of 100150=60
Adjusted frequency of 150200=70
Adjusted frequency of 200300=50
Adjusted frequency of 600800=45


Taking,
Xaxis=1unit=50 marks
Yaxis=1unit=10 student
Histogram of the above data is.



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