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Question

# Following is the frequency distribution of the total marks obtained by the students of all sections of a class in an examination. ​ Draw a histogram to represent the provided data.​

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Solution

## Class width = Upper limit – Lower limit For 100−150 Class width =150−100=50 Similarly, Class width of 150−200=50 Class width of 200−300=100 Class width of 300−600=300 Class width of 600−800=200 Now, Adjusted frequency = minimum class sizeclass size of this class×frequency Here, the minimum class size =50. Now, Adjusted frequency of class interval 300−600 is. Adjusted frequency = 50300×60 =10. Similarly, Adjusted frequency of 100−150=60 Adjusted frequency of 150−200=70 Adjusted frequency of 200−300=50 Adjusted frequency of 600−800=45 Taking, X−axis=1unit=50 marks Y−axis=1unit=10 student Histogram of the above data is.

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